# Who cares to help me with algebra?

ON Solving Equations with Variables on Both Sides

EX.

7x + 19 + (-2)x + 55

How do you solve that one?

and:

1/3(42 - 18z) = 2(8 - 4z)

No 2
14-6z=16-4z
4z+14-6z=16
2z=16-14
2z=2

1st can’t be properly soved as there is no equals:

7x+19-2x+55
5x+74

You have to get the variable on one side, and the numerics on the other. Remember that plus becomes minus as it crosses the equals sign, and vice versa.

I would have given you the answer right away, but that would have been pointless and not very effective in teaching you how.

Bad Vyse. You aren’t supposed to give away the answers, you’re supposed to give away the way to get to the answers.

Well, he didn’t actually solve it since 2z=2 isn’t really the answer. Besides, there’s not much you can do to help with a problem that has so few steps.

Written description of how to complete the second problem:
First, use the distributive property to seperate the variables from the constants. Once this is done, you can move all of the variables to one side, and all of the constants to the other side. This can be done by adding (or subtracting) an equal amount from both sides, since doing the same operation to both sides of the equation will not change its result. Finally, to determine the value of the variable, divide both sides by the coefficient.

Conserning Vyse’s 1st answer, you just forgot a couple of parts.

This is how it shoud look:

1/3(42 - 18z) = 2(8 - 4z)
14 - 6z = 16 - 8z

Other than that it looks right.

Then you just do what demigod said. Put all the ‘z-terms’ on one side, all the ‘numbers’ on the other. And solve it.