A math problem

Since you all are poo-poo heads who think you’re so smart and can answer setz’s math problem before me, here’s a conundrum for you. I’ll even explain the rule used in each step so you can see for yourselves that I’m not breaking any rules.

My Theory: 4=3

Proof:
Let a+b=c

a+b=c – premise
(4-3)a+(4-3)b=(4-3)c – addition property for equality
4a-3a+4b-3b=4c-3c – distributive property
4a+4b-3a-3b=4c-3c – communative property
4a+4b-4c=3a+3b-3c – addition property for equality
4(a+b-c)=3(a+b-c) – inverse distributive property
4=3 – multiplication property for equality

Therefore, 4=3.

Math must therefore be wrong and I’m a genius for proving it.

[spoiler]since a+b=c
a+b-c=0
4(0) = 3(0)
0=0

You’ve demsonstrated that you can prove anything if you can get people to miss that you divided by zero.[/spoiler]

Thanks, Mr. I look up answers to riddles and then tell them to everyone and spoil the whole thing or else I already knew the answer and spoiled it for everyone anyway. AKA Kraken. =(

Yeah kraken
You JERK.

That’s all I have, sorry

Sorry, didn’t know I had to <i>look up</i> the answer. I worked it out myself.

And wait: that qualifies as a riddle?

rid·dle
n.
<B>1. A question or statement requiring thought to answer or understand; a conundrum.</B>
2. One that is perplexing; an enigma.

You’re just upset that I pointed out the “trick” without recourse to outside sources.

ON the other hand, if I ever get REALLY bored, I can post an airtight mathematical proof that the human race doesn’t exist, based on the limit property of calculus and simple probability.

Do it! DOOO EEEET!

They’re all the same.

ooh. If you guys like math riddles or problems. I have a billion of em. Some that are even really hard to find if at all on google.

I like the ones that go like this:

Three guys went to a bar, and at the end of their drinking, the bill was \$27 (\$9 / person). They gave three \$10 bills to the waiter, who, for lack of smaller money, returned them a \$5 bill. The guys then gave a \$2 bill back to the waiter as a tip, so that each of them still kept his proper \$1 change.

Now, they paid \$27, plus the \$2 tip to the waiter, for a total of \$29. Where’s the last \$1?

Bartender screwed himself. They paid \$25 and the \$2 tip. >_>

edit: sorry, you’re right.

Spent in the end:
2 tens
1 five
1 \$2 bill
2 \$1 bills (assuming they paid the tip with one)

They end up with \$3 change from the \$5 the bartender gave them as change. Is that it? If not, I know it has something to do with the \$2 bill…

Redcomet was right. The trio gave the waiter \$30, received \$5 back, then gave him \$2 “as a tip” – except that 30 - 5 + 2 = 27, which was the cost of the drinks to begin with. In other words, they paid the full \$27 and included no tip. The riddle is entirely linguistic: it works because you unwittingly accept “as a tip,” which trips you up later.

But why explicitly state “a \$2 bill” and not just “gave back \$2”?

Sorry, I misread you RC. You were right in the first post (but the sum in the second still goes to \$29).

The \$2 bill is an attention trick.

Ah, alrighty. These are pretty fun. Anyone have any more?

I’ve heard this riddle before, only it involved a hotel and was much more difficult because it was told correctly.